1+11+111+1111.+111.11=?

1个回答

  • 1+11+111+1111+111...1 (111...1,有n个1)

    =1+(10+1)+(10^2+10+1)+(10^3+10^2+1)+...+[10^n+10^(n-1)+...1]

    =1×n+10(n-1)+10^2(n-2)+...+10^n[n-(n-1)]

    设Sn=1×n+10(n-1)+10^2(n-2)+...+10^n (1)

    10sn=10+10^2(n-1)+10^3(n-2)+...+10^(n+1)n(2)

    ∴(1)-(2):

    -9Sn=n+[10+10^2+10^3+10^n]-10^(n+1)n

    -9Sn=n-10^(n+1)+{10[1-10^n]/(1-10)}

    ={n-10^(n+1)}-{10[1-10^n]/9}

    ∴Sn={-{n-10^(n+1)}/9}-{10[1-10^n]/81}

    =10^(n+1)/9-(n/9)-{10[1-10^n]/81}