1、动量守恒:mv0=(M+m)v,则v=mv0/(M+m) ①
2、向心力=2(M+m)g=(M+m)v'^2/r,则在最高点的速度v'^2=2gr ②
又机械能守恒:0.5(M+m)v^2=(M+m)g*2r+0.5(M+m)v'^2 ③,综合①②③,解得r=m^2v0^2/(6g(M+m)^2)
3、动能定理:-(M+m)gh-μ(M+m)gcosθ*h/sinθ=0-0.5(M+m)v^2
解得h=m2v0^2/(2(M+m)^2(μcotθ+1)g)
1、动量守恒:mv0=(M+m)v,则v=mv0/(M+m) ①
2、向心力=2(M+m)g=(M+m)v'^2/r,则在最高点的速度v'^2=2gr ②
又机械能守恒:0.5(M+m)v^2=(M+m)g*2r+0.5(M+m)v'^2 ③,综合①②③,解得r=m^2v0^2/(6g(M+m)^2)
3、动能定理:-(M+m)gh-μ(M+m)gcosθ*h/sinθ=0-0.5(M+m)v^2
解得h=m2v0^2/(2(M+m)^2(μcotθ+1)g)