Question

如图,在平面直角坐标系中,正方形ABCD的边BC在x轴上,点E是对角线AC,BC的交点函数y=3/x的图象经过A,E两点

Answer 1

A坐标为(x,3/x)

E坐标为(x+3/2x,3/2x)

(x+3/2x)(3/2x) = 3

3/2 + 9/4x^2 = 3

9/4x^2 = 3/2

x^2 = 12/18 = 2/3

x = sqrt(2/3)

y = 3/sqrt(2/3) = 3sqrt(3/2) （A纵坐标）

OAE面积=1/2 AOC面积 = 1/4 (x+y)*y = 33/8