3k^2+11k+10
=(3k+5)(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12](3k+5)(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12
3k^2+11k+10
=(3k+5)(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12](3k+5)(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12