Question

根据下列条件求(0,2π)内的角X

Answer 1

sinx=-√3/2

x在二､四象限

x=-π/3+2kπ

x=4π/3+2kπ

sinx=-1

x=-π/2+2kπ

cosx=0

x=±π/2+2kπ

tanx=1

x在一、三象限

x=π/4+2kπ

x=5π/4+2kπ