设10g中含有NaHCO3 xg,Na2CO37H2O yg,那么含有Na2CO310H2O有(10-x-y)g
x/84+2y/232+2(10-x-y)/286=0.125*0.02*40 (1)
那么要求的是53x/84+106y/232+106(10-x-y)/286=?(2)
可以看出(1)左边乘以53即得(2),所以?=0.125*0.02*40*53=5.3g
设10g中含有NaHCO3 xg,Na2CO37H2O yg,那么含有Na2CO310H2O有(10-x-y)g
x/84+2y/232+2(10-x-y)/286=0.125*0.02*40 (1)
那么要求的是53x/84+106y/232+106(10-x-y)/286=?(2)
可以看出(1)左边乘以53即得(2),所以?=0.125*0.02*40*53=5.3g