2.5g铜溶入硫酸,铜变成硫酸铜同时产生二氧化硫和水等,硫酸铜溶入碘离子溶液,形成碘化亚铜和三碘化离子和硫酸根离子.三碘化离子用硫代硫酸钠滴定从而形成碘离子和S4O6^ 2离子,写出化学方程式,并计算如果滴定反应中消耗了21.5mL 的1.25mol/L的硫代硫酸钠,消耗掉的铜的质量百分比,
英语翻译A 2.50 gram of bronze was dissolved in sulfuric acid.The
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