sin2x-2sin^2x比上1--tanx
=(2sinxcosx-2sin²x)/[(cosx-sinx)/cosx]
=2sinx(cosx-sinx)/[(cosx-sinx)/cosx]
=2sinxcosx
=sin2x
cos(45+x)=0.6
√2/2(cosx-sinx)=0.6
1/2(cos²x+sin²x-2sinxcosx)=0.36
1-sin2x=0.72
sin2x=0.28
答案由此可见
sin2x-2sin^2x比上1--tanx
=(2sinxcosx-2sin²x)/[(cosx-sinx)/cosx]
=2sinx(cosx-sinx)/[(cosx-sinx)/cosx]
=2sinxcosx
=sin2x
cos(45+x)=0.6
√2/2(cosx-sinx)=0.6
1/2(cos²x+sin²x-2sinxcosx)=0.36
1-sin2x=0.72
sin2x=0.28
答案由此可见