1*1=1 ,(n+1)*1=3(n+1) ,求5*1-2*1=?
2个回答
(n+1)*1=3(n+1)
5*1-2*1=(4+1)*1-(1+1)*1=3(4+1)-3(1+1)=9
相关问题
lim(n→∝){1/(1*3)+1/(3*5)+...1/[(2n-1)*(2n+1)]} 求极限
1/1*3+1/3*5+1/5*7+.+1/(2n-1)(2n+1)=n/(2n+1)
1.1/1*2+1/2*3+1/3*4+……+1/n(n+1) 2.1/1*3+1/3*5+1/5*7+……+1/(2n
(1/n+1)*(1+1/3+1/5+…+1/2n-1)>=(1/n)*(1/2+1/4+…1/2n)
数学归纳法证明-1+3-5+.+(-1)^n(2n-1)=(-1)^n*n1/1*3+1/3*5+1/5*7+.+1/(
已知1*1+2*2+3*3+……+n*n=1/6n(n+1)(2n+1),求1*2+3*4+5*6+7*8+.+49*5
求算式1/1*2*3+1/2*3*4+1/3*4*5+…+1/n(n+1)(n+2)的值
试求使不等式[1/n+1+1n+2+1n+3+…+13n+1>5−2t
提问 根据式子1/N(N+1)=(N+1)-N/N(N+1)=1/N-1/(N+1),试求,1/1*2+1/2*3=1/
1/2-1/n+1<1/2^2+1/3^2+……+1/n^2<n-1/n(n=2,3,4,5,6.