Question

联立解b-c=根号3-1 bc=2+2根号3

Answer 1

+(-c)=√3-1

b*(-c)=-(2+2√3)

b,-c是关于方程x^2-(√3-1)x-(2+2√3)=0的2个根

[x+(1+√3)][x-2]=0

x=-√3-1或x=2

即b=-√3-1或b=2