Question

已知定义域为R的函数y=(-2^x+n)/(2^(x+1)+m)是奇函数 ​1 求m,n的值,并指出函数y=

Answer 1

（1）

f(0)=(n-1)/(2+m)=0 ==> n=1

故 f(x)=(1-2^x)/(2*2^x+m)

f(-x)=(1-2^(-x))/(2^(1-x)+m)

=(2^x-1)/(2+m*2^x)

=-f(x)

=-(1-2^x)/(2*2^x+m)

==> 2+m*2^x=2*2^x+m

==> m=2

故 y=f(x)=(1-2^x)/(2*2^x+2)

对于 s x>tx-2

x(t-1)