若2^n=9,4^m=3,求2^2n-4m+1=_____
2个回答
4^m=3--------两边取log得mlog4=log3
m=log3/log4
4m=4*(log3/log4)=log以四为底81,这上边写不出来
2^2n=81
相关问题
1.若m-n=4,mn=1,求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
若9^m=4分之1 3^n=2 求9^m+n
3M=2 3N=4 求9M+1-2n
若4∧m=3,8∧n=5,求2∧4m+9n的值
已知4m+n=9,2m-3n=1,求(m+2n)²-(3m-n)²的值
若4m²-9n²=27,且(2m+3n)=9
(m^2-6mn+9n^2)/(3n-m)-(4m^2-9n^2)/(2m-3n) m=-2 n=2008.化简求值
若(2m-n)2=3mn,求代数式n/m+4m/n-1的值
规定m※n=3m+2n 若X ※9=27 求2(X※4)的值