把圆心放在原点(0,0)考虑,设A(xa,ya),B(xb,yb),C(xc,yc),圆的半径为R
设AB之间逆时针转过的角度为α,有:
cosα=(xaxb+yayb)/R^2=m
sinα=(xayb-xbya)/R^2=n
讨论:
n≥0,α=acos(m)
n
把圆心放在原点(0,0)考虑,设A(xa,ya),B(xb,yb),C(xc,yc),圆的半径为R
设AB之间逆时针转过的角度为α,有:
cosα=(xaxb+yayb)/R^2=m
sinα=(xayb-xbya)/R^2=n
讨论:
n≥0,α=acos(m)
n