已知{x=sint^2 y=(2t+5)^2 求dy/dx
2个回答
dx/dt=2tcost^2
dy/dt=4(2t+5)
dy/dx=dy/dt÷dx/dt
=4(2t+5)/(2tcost^2)
=2(2t+5)/(tcost^2)
相关问题
x=2t^2 +1 y= sint 求dy/dx是多少?
参数方程:x=5(t-sint) y=5(1-cost) 求d^2y/dx^2 dy/dx我会求
设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tc
x=sint+1 y=2cos3t dy/dx
设{x=sint y=cos2t,则dy/dx|t=π/4=
此参数方程为什么这么解x=2(t-cost)y=2(1-sint)求dy/dx.答案是dy/dx = -cost/(1+
此参数方程怎么解?x=2(t-cost)y=2(1-sint)求dy/dx.为什么是这样解呢?dx= 2(1+sint)
已知参数方程x=t+t^2,y=cost.求导数dy/dx和d^2y/dx^2
已知z=x^2+y^2 z=x+y 求dy/dx= ,dz/dx=
已知 x=e^t ,dy/dx=dy/xdt .分析变换具体步骤 d^2y/dx^2=(d^2y/dt^2-dy/dt)