【(x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2/3的负二次方)】除以(-3x)的负一次方
=[x²-(2y-3/2)²+4y²-6y+（3/2）²]÷1/(-3x)
=[x²-4y²+6y-(3/2)²+4y²-6y+（3/2）²]×(-3x)
=x²×(-3x)
=-x³
x=-1,原式=-（-1）³=1
一元二次方程X的平方-(M的平方+3)X+1/2(M的平方+2)=0
判别式Δ=（M²+3）²-2(M²+2)=M^4+4M²+5=(M²+2)²+1
(M²+2)²+1恒≥1,方程必有两个实根
又,x1+x2=M²+3≥0,x1x2=M²+2≥0
所以,方程有两个正根
x的平方-1 分之 x的平方-2x+1除以（x的平方+x 分之 x-1）-x
=(x²-2x+1)/(x²-1)÷[（x-1）/(x²+x)]-x
=(x-1)²/(x-1)(x+1)÷[（x-1）/x(x+1)]-x
=(x-1)/(x+1)×[x(x+1)/(x-1)]-x
=x-x
=0
无论x取何值,结果都为0