因为在三角形ABC中,三个角都大于0小于180,
所以cosC==√2/2,cosB=√5/5
sinA=sin((180-(A+C))
=sin180*cos(B+C)-cos180*sin(B+C)
=sin(B+C)=sinB*cosC+cosB*sinC
=(2√5)/5*√2/2+√5/5*√2/2
=(3√10)/10
因为在三角形ABC中,三个角都大于0小于180,
所以cosC==√2/2,cosB=√5/5
sinA=sin((180-(A+C))
=sin180*cos(B+C)-cos180*sin(B+C)
=sin(B+C)=sinB*cosC+cosB*sinC
=(2√5)/5*√2/2+√5/5*√2/2
=(3√10)/10