3﹙x²-27﹚-3/4x²
=3﹙x²-27-1/4x²﹚
=3﹙3/4x²-27﹚
=9﹙1/4x²-9﹚
=9﹙1/2x+3﹚﹙1/2x-3﹚
﹙x+y﹚⁴-﹙x-y﹚⁴
=[﹙x+y﹚²]²-[﹙x-y﹚²]²
=[﹙x+y﹚²+﹙x-y﹚²][﹙x+y﹚²-﹙x-y﹚²]
=﹙2x²+2y²﹚[x+y-﹙x-y﹚]﹙x+y+x-y﹚
=2﹙x²+y²﹚﹙2y﹚﹙2x﹚
8﹙x²+y²﹚xy
3﹙x²-27﹚-3/4x²
=3﹙x²-27-1/4x²﹚
=3﹙3/4x²-27﹚
=9﹙1/4x²-9﹚
=9﹙1/2x+3﹚﹙1/2x-3﹚
﹙x+y﹚⁴-﹙x-y﹚⁴
=[﹙x+y﹚²]²-[﹙x-y﹚²]²
=[﹙x+y﹚²+﹙x-y﹚²][﹙x+y﹚²-﹙x-y﹚²]
=﹙2x²+2y²﹚[x+y-﹙x-y﹚]﹙x+y+x-y﹚
=2﹙x²+y²﹚﹙2y﹚﹙2x﹚
8﹙x²+y²﹚xy