sin2x+cos2x
=asin2x+bcos2x
=√1+1（√2/2sin2x+√2/2cos2x）
=√2（cos派/4in2x+sin派/4cos2x)
=√2sin(2x+派/4)
sin2x+cos2x 怎么得出等于 根号2sin(2x+派/4)
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