Question

一道路方程应用题现有3600盆甲种花,和2900盆乙种花反搭配A,B种造形共50个,造型A：甲:90盆,乙30盆.造型B

Answer 1

设A种造型搭配的有X个,则B种的有(50-X)个

90X+40(50-X)小于等于3600 30X+100(50-X)小于等于2900

所以30小于等于X小于等于32 因为X为正整数 所以X1=30 X2=31 X2=32

1 A30 B20 2 A31 B19 3 A32 B18

1000X30+1200X20=54000 1000X31=1200X19=53800

1000X32+1200X18=53600 所以方案3最低