f(-x)=-xsin(-5x-5/2丌)
= xsin(5x-3/2 丌)
=xsin(5x+1/2 丌)
=xcos5x
f(x)=xsin(5x-1/2丌)=-xcos5x
所以f(x)=-f(-x),所以函数是奇函数!
判断函数的奇偶性:y=xsin(5x-5/2丌)
f(-x)=-xsin(-5x-5/2丌)
= xsin(5x-3/2 丌)
=xsin(5x+1/2 丌)
=xcos5x
f(x)=xsin(5x-1/2丌)=-xcos5x
所以f(x)=-f(-x),所以函数是奇函数!