Question

将0.2mol/LCuSO4溶液和1.0mol/LH2SO4溶液等体积混合.计算

Answer 1

因为是等体积,所以设体积为1L

n(CuSO4)=0.2mol/L*1L=0.2mol

n(H2SO4)=1.0mol/L*1L=1.0mol

假如混合后总体积不变,

则c(CuSO4)=0.2mol/2L=0.1mol/L

c(H2SO4)=1.0mol/2L=0.5mol/L

c(Cu2+)=c(CuSO4)=0.1mol/L

c(H+)=2c(H2SO4)=0.5mol/L*2=1mol/L

c(SO42-)=[n(CuSO4)+n(H2SO4)]/V=1.2mol/2L=0.6mol/L