[1^2+2^2+3^2+...+(n-1)^2]
=n(n-1)(2n-1)/6
=(2n^3-3n^2+n)/6
lim[1^2+2^2+3^2+...+(n-1)^2]/(5n^4)
=lim[(2n^3-3n^2+n)/6]/(5n^4)
=1/30lim(2/n-3/n^2+1/n^3)
=0 (n->+∞)
lim (1^2+2^2+3^2+...+(n-1)^2)/5n^4
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