由公式sinx=sin(π-x)而来
f(x)=2sin(π/6-2x)=2sin(2x+5π/6)是怎样转换过来的,求详解
1个回答
相关问题
-
若f(x)=2sin(π/6-2x),当f(x)=1/2时,求sin(5π/6+2x)+sin²(π/3+2x
-
10.sin2(π/3 -x)+sin2(π/6 +x)=________ _; 望详解
-
已知函数f(x)=2sin(x+π/6)-2sin(π/2+x) x∈[π/2,π]
-
f(x)=sin(x+π/6)+sin(x-π/6)+2cos^2(x/2)+a,求最小正周期,[-π/2,π/2]上最
-
f(x)=sin(2x-π/6),π/4≤x≤π/2,求f(x)的值域
-
求函数f(x)=2sin²x+2sinx-1/2,x∈[π/6,5π/6]的值域
-
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
-
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+2cos²x
-
已知函数f(x)=sin(2x+π/6)+sin(2x -π/6)+2cos²x
-
已知函数f(x)=sin(x+π/6)+sin(x-π/6)-2cos^2(x/2),x∈[0,π] 求化简函数f(x)