Question

（有图）高二文科数学空间点、直线、平面之间的位置关系（要详细的过程）

Answer 1

(1)已知图形是长方体,则：AA'=CC',AA'‖CC'∴AA'C'C是平行四边形,∴AA'‖AC,即求∠ACB.AB=2倍根号下3,AD=BC=2倍根号下3,又∵∠ABC=90,AB=BC.∴∠ACB=45.

(2)∵AA'‖CC',∴即求∠BC'C,∵AA'=CC'=2,AD=BC=2倍根号下3,

∴tan∠BC'C=2倍根号下3/2,即∠BC'C=60.