运用提携公式,提出2
所以原式变为:2(1/2sinπ/12 - √3/2cos π/12)
原式:2(1/2sinπ/12 - √3/2cos π/12)
=2(cosπ/3*sinπ/12 - sinπ/3*cos π/12)
=2sin(π/12 -π/3)
=2sin(-π/4)
=-√2
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运用提携公式,提出2
所以原式变为:2(1/2sinπ/12 - √3/2cos π/12)
原式:2(1/2sinπ/12 - √3/2cos π/12)
=2(cosπ/3*sinπ/12 - sinπ/3*cos π/12)
=2sin(π/12 -π/3)
=2sin(-π/4)
=-√2
知道证书很荣幸为你解答问题,欢迎你问,欢迎你再问!(模仿麦当劳服务语)