三角形ABC中,角B=角A+20°,角C=角B+2 - 知识问答

三角形ABC中,角B=角A+20°,角C=角B+20°,求三角形ABC的度数,明天要交的啊

1个回答

角C=角B+20°
=角A+20°+20°
=角A+40°
角A+角B+角C=180°
角A+角A+20°+角A+40°=180°
3角A+60°=180°
3角A=120°
角A=40°
角B=角A+20°=40°+20°=60°
角C=角A+40°=40°+40°=80°

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