∵AB＝CD,AE＝CF,BE＝DF
∴三角形ABE全等三角形CDF
∴∠AEB=∠CFD
∵∠AEF=180-∠AEB
∠CFE=180-∠CDF
∴∠AEF=∠CFE
∴AE∥CE
∵AE=CF
∴AECF是平行四边形
AF∥CE
已知：如图,AB＝CD,AE＝CF,BE＝DF.求证：AF∥CE
1个回答
相关问题
-
如图,已知ABⅡCD,OA=OD,AE=DF,求证：BEⅡCF.
-
如图AB=CD AF∥DF CF∥BE 求证AF=DE
-
如图,已知BE=DF,AE=CF,AE∥CF,说明AB∥CD
-
如图,已知CE⊥AB,DF⊥AB,AF=BE,CE=DF,求证AC//BD
-
已知如图AB=DC,AE=DF,CE=FB求证AF=DE
-
如图AB=CD,BE=CF,AE=DF求证OA=OD
-
AB=CD,BE=DF,AF=CE求证BE‖DF
-
如图,AB=DC,AF=DE,CF=BE,∠AFD=∠DEA.求证:AE‖DF.
-
如图:AB=CD,AE=DF,CE=FB.求证:AE∥DF
-
如图,已知AB=AC,AE=CF,BE=AF,求证：∠E=∠F.