Question

loga^b的倒数是logb^a?

Answer 1

是

loga^b*logb^a

=(logc^b/logc^a)*(logc^a/logc^b)

=1

loga^b×logb^c×logc^a

=(logm^b/logm^a)*(logm^c/logm^b)*(logm^a/logm^c)

=1

利用换底公式

loga^b

=logc^b/logc^a