x=1/(√7+√5)=(√7-√5)/2
y=1/(√7-√5)=(√7+√5)/2
所以
x+y=(√7-√5)/2 + (√7+√5)/2=√7
xy=(√7-√5)/2 X (√7+√5)/2=1/2
x/y +y/x
=(x²+y²)/xy
=[(x+y)²-2xy]/xy
=(7-1)/(1/2)
=12
x=1/(√7+√5)=(√7-√5)/2
y=1/(√7-√5)=(√7+√5)/2
所以
x+y=(√7-√5)/2 + (√7+√5)/2=√7
xy=(√7-√5)/2 X (√7+√5)/2=1/2
x/y +y/x
=(x²+y²)/xy
=[(x+y)²-2xy]/xy
=(7-1)/(1/2)
=12