Question

若m为整数,m>2,则8(x+2y)的m+1次方÷[-(x+2y)]的m-1次方=?

Answer 1

8(x+2y)的m+1次方÷[-(x+2y)]的m-1次方=?

m为奇数时,原式=8(x+2y)²;

m为偶数时,原式=-8(x+2y)²;