弧长C=6米,拱高H=0.2米,求弦长L?
弧半径为R,弧所对的圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=22
R1=22.448
R2=22.467
R3=22.467
R=22.467米
A=C/R=6/22.467=0.267058弧度=0.267058*180/PI=15.3度
L=2*R*SIN(A/2)
=2*22.467*SIN(15.3/2)
=5.982米
弧长C=6米,拱高H=0.2米,求弦长L?
弧半径为R,弧所对的圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=22
R1=22.448
R2=22.467
R3=22.467
R=22.467米
A=C/R=6/22.467=0.267058弧度=0.267058*180/PI=15.3度
L=2*R*SIN(A/2)
=2*22.467*SIN(15.3/2)
=5.982米