Question

（x-c-b)/a+(x-a-c)/b+(x-a-b)/c=3,1/a+1/b+1/c不等于零,求x-a-b-c

Answer 1

(x-c-b)/a+(x-a-c)/b+(x-a-b)/c-3=0

把-3拆成-1-1-1

[(x-c-b)/a-1]+[(x-a-c)/b-1]+[(x-a-b)/c-1]=0

(x-a-c-b)/a+(x-a-c-b)/b+(x-a-c-b)/c=0

(x-a-c-b)(1/a+1/b+1/c)=0

1/a+1/b+1/c不等于零

所以x-a-b-c=0