(1)
y的4次方-y²=6
y的4次方-y²-6=0
(y²-3)(y²+2)=0
(y+√3)(y-√3)(y²+2)=0
∴y=√3或y=-√3
(2)第二题应该是:(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)+8=0
[(y+1)-4][(y+1)-2]=0
(y-3)(y-1)=0
∴y=3
或y=1
(1)
y的4次方-y²=6
y的4次方-y²-6=0
(y²-3)(y²+2)=0
(y+√3)(y-√3)(y²+2)=0
∴y=√3或y=-√3
(2)第二题应该是:(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)+8=0
[(y+1)-4][(y+1)-2]=0
(y-3)(y-1)=0
∴y=3
或y=1