Question

已知函数y1=a^(x^2-2x+3)和y2=a^(2x^2+4x+3),问当x取什么值时(1)y1=y2,(2)y1>

Answer 1

y1=y2

=>a^(x^2-2x+3)=a^(2x^2+4x+3)

=>x^2-2x+3=2x^2+4x+3

=>x=0 ,x=-6

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y1>y2

=>a^(x^2-2x+3)>a^(2x^2+4x+3)

(这里与a 有关,如果a>1)

=>-6