(1)
(2x-5)² - (x+4)² = 0
(2x-5) = ± (x+4)
2x-5 = x+4,x1 = 9
2x-5 = - (x+4) ,2x-5 = - x - 4 ,x2 = 3
(2)
(x+2)² - 10(x+2) + 25 = 0
(x+2 +5)(x+2 -5) = 0
(x+7)(x-3) = 0
x1 = -7
x2 = 3
(1)
(2x-5)² - (x+4)² = 0
(2x-5) = ± (x+4)
2x-5 = x+4,x1 = 9
2x-5 = - (x+4) ,2x-5 = - x - 4 ,x2 = 3
(2)
(x+2)² - 10(x+2) + 25 = 0
(x+2 +5)(x+2 -5) = 0
(x+7)(x-3) = 0
x1 = -7
x2 = 3