Question

已知log3(2)=a,2^b=3,求lga+lgb的值

Answer 1

log3(2)=a推出3^a=2 ①

2^b=3 ②

将①②得：3^a（^b）＝3^（ab）＝3推出ab＝1

lga+lgb＝lgab＝lg（1）＝0