x+y+z=3,3x-y-4z=-2,2x+3y-2z=3
2个回答
就写成X=3-Y-Z代入后两个方程,化为了二元一次方程组,
最后答案貌似是x=y=z=1
相关问题
证明:(y+z-2x)3+(z+x-2y)3+(x+y-2z)3=3(y+z-2x)(z+x-2y)(x+y-2z).
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已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=?
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