Question

一道高中计算题已知sin(a+b)=0.5,sin(a-b)=1/3,求tana/tanb

Answer 1

sin(a+b)=0.5,sin(a-b)=1/3,两式相加得sinacosb=5/12

sinbcosa=1/12

tana/tanb =(sinacosb)/(sinbcosa)=5