a增加p%得b
a(1+p%)=b
b/a=1+p%
b减少q%得a
b(1-q%)=a
b/a=1/(1-q%)
所以1+p%=1/(1-q%)
(1+p/100)(1-q/100)=1
1-q/100+p/100-pq/10000=1
pq/10000-p/100+q/100=0
pq-100p+100q=0
a增加p%得b
a(1+p%)=b
b/a=1+p%
b减少q%得a
b(1-q%)=a
b/a=1/(1-q%)
所以1+p%=1/(1-q%)
(1+p/100)(1-q/100)=1
1-q/100+p/100-pq/10000=1
pq/10000-p/100+q/100=0
pq-100p+100q=0