(1) EF=BE+DF
(2)2∠EAF=∠BAD 证明:将三角形ABE旋转至ADE'
∠B+∠D=180°则FDE'共线
AE=AE' AF=AF EF=BE+FD=E'F
△AEF全等于△AE'F ∠EAF=∠E'AF 即 2∠EAF=∠BAD
(1) EF=BE+DF
(2)2∠EAF=∠BAD 证明:将三角形ABE旋转至ADE'
∠B+∠D=180°则FDE'共线
AE=AE' AF=AF EF=BE+FD=E'F
△AEF全等于△AE'F ∠EAF=∠E'AF 即 2∠EAF=∠BAD