（x2+y2）（x-y）-（x2-y2）（x+y）

4个回答

1.(x-2y)(x+2y)-(x平方+y)(x平方-y) 2.(2x-y)(y+2x)-(2y+x)(2y-x)
[(X-2Y)²+（x-2y）(x+2y)-2x(2x-y)]/2X
计算：[(x+y/x-y)^2·(2y-2x/3x+3y)]-[(x^2/x^2-y^2)/(x/y)]
(x-y)(x+y)=x^2-y^2 (x-y)(x^2+xy+y^2)=x^3-y^3 (x-y
[（x-2y)^2+(x-2y)(x+2y)-2x(2x-y)]/2x
(x+2y)(x-2y)-(2x-y)(-2x-y)
(2x+y)²-2(2x+y)(x-y)+(x-y)²
计算(x^2-y^2)/(x+y)-[4x(x-y)x+y^2]/2x-y
(3x-2y)²-(2x-y)(2x-3y)+(2x+y)(2x-y)
=[y^2*x+x-y-x^2*y]/[(x^2+1)(y^2+1)] =[(x-y)+xy(y-x)}/[(x^2+1