Question

(e∧x－e∧－x）∧2零到一,求定积分,怎么化

Answer 1

原式=∫(0,1)(e^2x-2+e^(-2x))

=1/2e^2x|(0,1)-2-1/2e^(-2x)|(0,1)

=1/2(e^2-1)-2-1/2(e^(-2)-1)

=(e^2-e^(-2))/2 -2