Question

每空五分绝对给发电厂输出功率为9900kW,输电线电阻为2欧姆,分别用18kV和110kV的高压输电,则导线上损失的功率

Answer 1

18kV输电：I=P/U1=(9900 x 10^3)/(18 X 10^3)=550A

则P损=I^2R=550^2 x 2=605000w=605kw

110kV输电：I=P/U2=(9900 x 10^3)/(110 X 10^3)=90A

则P损=I^2R=90^2 x 2 =16200w=16.2kW