原式=[(x²+3)/(x²-1)-2/(x-1)]/[x(x-1)/(x+1)-1/x-1={[(x²+3-2(x+1)]/[(x+1)(x-1)]} (x+1)/[x(x-1)]-1/x-1=[(x-1)²/(x-1)]/[x(x-1)]-1/x-1=1/x-1/x-1=1
[(x^2+3)/(x^2-1)+2/(1-x)]/(x^2-x)/(x+1)-1/x+1
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