1.mFe:mO=21:8所以Fe和O原子个数比为21/56:8/16=3:4所以Fe2O3:FeO=1:1
Fe2O3被还原的百分率为33.3%
(2)[(1-A%)*2/120+2*A%/120]:[(1-A%)*3/120+A%*2/120]=2:(3-A%)
1.mFe:mO=21:8所以Fe和O原子个数比为21/56:8/16=3:4所以Fe2O3:FeO=1:1
Fe2O3被还原的百分率为33.3%
(2)[(1-A%)*2/120+2*A%/120]:[(1-A%)*3/120+A%*2/120]=2:(3-A%)