(x²-2x)(x²-2x+2)+1
=(x²-2x)²+2(x²-2x)+1
=(x²-2x+1)²
=(x-1)的4次方
2(a²+b²)(a+b)²-(a²-b²)²
=2(a²+b²)(a+b)²-(a+b)²(a-b)²
=(a+b)²[2a²+2b²-(a-b)²]
=(a+b)²[a²+b²+2ab]
=(a+b)²(a+b)²
=(a+b)的4次方
(x²-2x)(x²-2x+2)+1
=(x²-2x)²+2(x²-2x)+1
=(x²-2x+1)²
=(x-1)的4次方
2(a²+b²)(a+b)²-(a²-b²)²
=2(a²+b²)(a+b)²-(a+b)²(a-b)²
=(a+b)²[2a²+2b²-(a-b)²]
=(a+b)²[a²+b²+2ab]
=(a+b)²(a+b)²
=(a+b)的4次方