1 .sin10sin50sin70=cos10sin10sin50sin70/cos10
=[1/2(sin20cos20cos40)]/cos10
=(1/4sin40cos400/cos10
=(1/8sin80)/cos10
=1/8
2 .tan-α=tan[(π|4-α)-π|4]=[tan(π|4-α)-tan(π|4)]/1+tan(π|4-α)
=1/2
所以tanα=-1/2
cotα等于1/tanα=-2
1 .sin10sin50sin70=cos10sin10sin50sin70/cos10
=[1/2(sin20cos20cos40)]/cos10
=(1/4sin40cos400/cos10
=(1/8sin80)/cos10
=1/8
2 .tan-α=tan[(π|4-α)-π|4]=[tan(π|4-α)-tan(π|4)]/1+tan(π|4-α)
=1/2
所以tanα=-1/2
cotα等于1/tanα=-2