Question

x三次-27分之x平方+3x+9+9-x分之6-6+2x分之x-1

Answer 1

是9-x²分之6

原式=(x²+3x+9)/(x-3)(x²+3x+9)-6/(x-3)(x+3)-(x-1)/2(x+3)

=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)

=[2(x+3)-12-(x-1)(x-3)/[2(x+3)(x-3)]

=(2x+6-12-x²+4x-3)/[2(x+3)(x-3)]

=-(x²-6x+9)/[2(x+3)(x-3)]

=-(x-3)²/[2(x+3)(x-3)]

=(3-x)/(2x+6)