CH4(g)+H2O(g)------CO(g)+3H2(g);△H>0
1mol 2mol
(1-x)mol (2-x)mol x mol 3x mol
(1 3 1 3) 解得
1-x+2-x+x+3x=4 mol
x=0.5 mol
0.5/1=50%
所以a:b:c:d=1:3:1:3
CH4(g)+H2O(g)------CO(g)+3H2(g);△H>0
1mol 2mol
(1-x)mol (2-x)mol x mol 3x mol
(1 3 1 3) 解得
1-x+2-x+x+3x=4 mol
x=0.5 mol
0.5/1=50%
所以a:b:c:d=1:3:1:3