Question

/ab/+(b-1)的2次方=0,求ab分之1+（a+2)(b+1)分之1,+(a+2)(b+2)分之1.+(a+200

Answer 1

/ab/+(b-1)的2次方=0

有:ab=0,(b-1)^2=0

a=0,b=1,

ab分之1+（a+2)(b+1)分之1,+(a+2)(b+2)分之1.+(a+2000)(b+2000)分之1

=1/0

题目有问题.!